CurryInfo: currypp-3.2.0 / CPP.ICode.ParsePos.movePosByChar
definition: 
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movePosByChar :: Pos -> Char -> Pos
movePosByChar (Pos f a x y) c | c == '\n' = Pos f (a+1) (x+1) 1
| c == '\t' = Pos f (a+1) x (y+tw-mod (y-1) tw)
| otherwise = Pos f (a+1) x (y+1)
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demand:
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argument 1 |
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deterministic:
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deterministic operation |
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documentation:
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Move the position one character |
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failfree:
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<FAILING> |
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indeterministic:
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referentially transparent operation |
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infix:
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no fixity defined |
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iotype:
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{({Pos},_) |-> {Pos}}
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name:
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movePosByChar |
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precedence:
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no precedence defined |
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result-values:
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{Pos}
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signature:
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Pos -> Prelude.Char -> Pos |
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solution-complete:
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operation might suspend on free variables |
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terminating:
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possibly non-terminating |
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totally-defined:
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possibly non-reducible on same data term |