| definition: |
fromPosition :: Position -> Span fromPosition NoPos = NoSpan fromPosition p@(Position _ _) = Span p p |
| demand: |
argument 1 |
| deterministic: |
deterministic operation |
| documentation: |
-- | Create a Span with the given Position as start and end |
| failfree: |
_ |
| indeterministic: |
referentially transparent operation |
| infix: |
no fixity defined |
| iotype: |
{({NoPos}) |-> {NoSpan} || ({Position}) |-> {Span}}
|
| name: |
fromPosition |
| precedence: |
no precedence defined |
| result-values: |
{NoSpan,Span}
|
| signature: |
Curry.Position.Position -> Span |
| solution-complete: |
operationally complete operation |
| terminating: |
yes |
| totally-defined: |
reducible on all ground data terms |